Question

the sum two digits of a two digit number is 15. If the number formed by reserving the digits is less than the original number by 27, find the original number​

Answer 1

Answer:

let the numbers be X and y

X+y =15.

10y+x-10x-y = 27

9x-9y=27

x-y=3

by solving

x+y=15. and

x-y=3

we get x=9. and y=6

so the number is 96

Answer 2

Answer:

the answer is 96.

Step-by-step explanation:

lets assume the digits to be x, y.

now, x+y=15.

the possible combination will be

(9,6)

(8,7)

since the reverse is smaller than original number ( stated in question)

after checking the difference between the combination you will find that (9,6) only hold against the difference of 27.

hence, the original number is 96.