The sum two positive no.s is 108 and diff. of those no. is 8 find the no
Answers
Answered by
7
Hi there
Your answer is :-
Let the 2 numbers be x and y
x+y = 108 ------------------->1
x-y = 8 ------------------->2
(1) - (2)
2y = 100
y= 50
x= 58
∴ The numbers are 50 and 58 ( Ans )
Thank You
Your answer is :-
Let the 2 numbers be x and y
x+y = 108 ------------------->1
x-y = 8 ------------------->2
(1) - (2)
2y = 100
y= 50
x= 58
∴ The numbers are 50 and 58 ( Ans )
Thank You
Answered by
4
Hello!!
Here is your answer.
Let the two numbers be a and b.
ATQ...
a + b = 108 (i)
a - b = 8. (ii)
Adding both equations. ....
a + b = 108
a - b = 8
----------------
2a = 116
a = 58.
Putting a = 58 in equation (i), we get
b = 108-58 = 50.
Hence, the two numbers are 58 and 50.
Hope It Helps
Here is your answer.
Let the two numbers be a and b.
ATQ...
a + b = 108 (i)
a - b = 8. (ii)
Adding both equations. ....
a + b = 108
a - b = 8
----------------
2a = 116
a = 58.
Putting a = 58 in equation (i), we get
b = 108-58 = 50.
Hence, the two numbers are 58 and 50.
Hope It Helps
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