Question

The sum up to the infinite terms of an GP is 16 and common ratio is 0.5 then find fourth term.

Answer 1

Answer:4

Explanation:

a(1-r)=16

a(1-r)=16r=0.5

a(1-r)=16r=0.5a(1-0.5)=16

a(1-r)=16r=0.5a(1-0.5)=16a×0.5=16

a(1-r)=16r=0.5a(1-0.5)=16a×0.5=16a=16/.5=32

a(1-r)=16r=0.5a(1-0.5)=16a×0.5=16a=16/.5=324th therm=ar^n-1=32×(.5)^(4-1)

a(1-r)=16r=0.5a(1-0.5)=16a×0.5=16a=16/.5=324th therm=ar^n-1=32×(.5)^(4-1)4.