Question

the sums of n, 2n,3n terms of an ap are s1,s2,and s3 respectively . prove that s3=3(s2-s1)

Answer 1

Answer:

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Step-by-step explanation:

S1=n/2 (2a+(n-1)d)

S2=2n/2(2a+(2n-1)d)

S3=3n/2(2a+(3n-1)d)

S2-S1= 2a*n+nd(3n-1) /2

= n/2 (2a+(3n-1)d)

=S3/3= S2-S1

S3=3(S2-S1)

Hence proved