Math, asked by reshmarsharief, 10 months ago

The sums of n terms of two arithmetic progressions are in the ratio 3n+1:7n-3; find the ratio of their 11" terms.
The ratio of their 11 th terms =
(Write the ratio in the lowest form)please correct answer

Answers

Answered by seemathakur3451

1

Step-by-step explanation:

nvd c oggx s hiafgjzizgjfs

Answered by adityavajpayee001

0

Answer:

as the sum of n term is in the ratio so the n term will be let x and let n2 be y x+y=the ration given the ratio is not possible so it is nt

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