Question

the sums of parallel sides of a trapezium is 25 cm abd its area is 150cm² find its altiude do the solution quickly with the steps by steps​

Answer 1

ANSWER:

• Altitude (height) of Trapezium = 12 cm

GIVEN:

• Sum of parallel sides of a trapezium is 25 cm
• Area of trapezium = 150 cm².

TO FIND:

• Altitude of trapezium.

SOLUTION:

Formula

$area \: of \: trapezium \: = \frac{1}{2} (sum \: of \: parallel \: side) \: \times height$

Putting the values we get;

$\implies \: 150 = \frac{1}{2} \times 25 \times height \\ \\ \implies \: 150 = \frac{25}{2} \times height \\ \\ \implies \: 150 \times \frac{2}{25} = height \\ \\ \implies \: height \: = 12 \: cm$

So Altitude (height) of Trapezium = 12 cm

NOTE:

some important formulas:

• Area of parallelogram = Base * Altitude
• Area of rhombus = (Base * Altitude ) OR

$= \frac{1}{2} \times (product \: of \: their \: diagonal)$