Math, asked by kartik9011, 1 year ago

the sun of the digits of a two digit number is 13 if the number obtained by reversing the digit is 45 more than the original number find the original number​

Answers

Answered by ujjwalpratap73
0

Answer:

13+13-45=196497384285455

Answered by abhimanyu4692
0

Answer:

-131

Step-by-step explanation:

let the two digit number be xy . So, it can be written as 10x+y .

x+y=13 it is equation number 1.

after reserving the number xy we get yx and it can be written as 10y+x

according to question after reservingwe get 45 more then original.

So, 10x+y=10y+x-45

= 9x-9y=-45

= x-y=-5 it is equation 2

now subtract both equation.................  x+y=13

                                                               x-y= -45

                                                               2y=58

                                                                y=29

so x+29=13

x=13-29

x=-16

so original number is 10*-16+29

= -160+29

= -131

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