The Sun of the Squre of two
consecutive natural number is 421. find the greater number
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Step-by-step explanation:
Let one number= x
Consecutive number= x+1
square of the one number=x^2
square of the consecutive number=(x+1)^2
sum of square of two consecutive natural numbers =421..................(given)
x^2+(x+1)^2=421
x^2+x^2+1+2x=421
2x^2+2x=421-1
2x^2+2x=420
2(x^2+x)=420
x^2+x=210
x^2+x-210=0
x^2+14x-15x-210=0
x(x+14)-15(x+14)=0
x+14=0,x-15=0
x=-14,x=15
One number=-14(or)15
Consecutive number=16 (or)-13
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