Question

The sun of two numbers is 528 and their H.CF is 33. Find the number of pairs of such
numbers satisfying the above condition?
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Answer 1

Step-by-step explanation:

we know that """""H.CF×L.C.M=A+B

Now A+B=528

and H.C.F=33

Therefore by applying formula we have

33×L.C.M=528

~~L.C.M=16

HOPE IT HELPS YOU

Answer 2

Answer:

HCF=33 and the product of number=528

hence, HCF x LCM = 1st no. x 2nd no.

so, 33 x LCM = 528

then, LCM = 16 .....

HOPE THIS WILL HELP U..