Question

the Sun's elevation is 60° then a pole of height 6m will cast a shadow of length
$6 \sqrt{3}$
(b)
$\sqrt{3}$
(c)
$2 \sqrt{3}$
tell me the answer and explain



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Answer 1

QUESTION:

If the Sun's elevation is 60° then a pole of height 6m will cast a shadow of length:-

a) 6√3 m

b) √3 m

c) 2√3 m

ANSWER:

Option C, 2√3 m

SOLUTION:

Angle of elevation is 60⁰ [Given]

Height of the pole is 6m [Given]

● In right triangle ABC, AB is the height of the pole and BC is the length of the shadow.

==> Tan 60⁰ = Opposite side/ Adjacent side

==> Tan 60⁰ = AB/BC

==> √3 = 6/BC

==> BC = 6/√3

==> BC = 6√3/3 [Conjugate Multiplication]

==> BC = 2√3

∴ Length of side BC = 2√3 m

∴ Length of shadow is 2√3 m

Answer 2

I don't know the answer...