Question

The sunm of 7 consecutive numbers is 168. What is the sum of first & last number?

Answer 1

the sum of the first and last numbers is 48.

Given,

The sum of seven consecutive numbers = 168

To Find,

sum of the first and last numbers

Solution,

We can simply solve this numerical problem by using the following process.

Now,

Let the 7 consecutive numbers be x , x+1 , x+2 , x+3 , x+4 , x+5 , x+6 .

x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)+(x+6)  = 168        

7x + 21 = 168

 7x = 168 - 21

7x = 147

x = 147 / 7

x = 21

                                                             

first number is: x=21

last number is: (x+6) = 21+6

= 27

sum of the first and last numbers = 21+27

 = 48

Hence, the sum of the first and last numbers is 48.

Answer 2

The sum of the first and last numbers is 48.

Given:

The sum of 7 consecutive numbers the s 168.

To Find:

The sum of the first & last number.

Solution:

To find the sum of the first and last number we will follow the following steps:

As we know,

Let the 7 consecutive numbers be x, x + 1, x + 2, x + 3, x + 4, x + 5, x + 6.

Now,

The sum of these consecutive numbers = 168

So,

x + (x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) + (x + 6) = 168

7x + 21 = 168

7x = 168 - 21

7x = 147

$x = \frac{147}{7} = 21$

x = 21

So,

The first number x = the 21

The last number (x + 6) = 21 + 6 = 27

The sum of the first & last numbers = 21 + 27 = 48.

Henceforth, the sum of the first & last numbers is 48.

#SPJ2