Question

the supplement of (90°-x/2) is

please answer the questions​

Answer 1

Answer:

90° -x/2

transpose x/2 to LHS

(x/2)= 90

x= 90 x 2

x=180

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Answer 2

Answer:

$supplement \: of \: \alpha = 180 - \alpha$

so supplement of (90–x/2) = 180–(90–x/2)= 90°+x/2

ans.