The supplement of an angle is one - third of it. Determine the angle and it's supplement .
ANSWER= angle 135° and supplement = 45° but how????
Answers
Answered by
27
let an angle be x.
then its supplement=180-x.
A/Q
SUPPLEMENT OF ANGLE =one third of the angle
180-x=x/3
3(180-x)=x.
540-3x=x
-3x-x=-540
-4x=-540
x=135degree
and its supplement=180-135=45degree
then its supplement=180-x.
A/Q
SUPPLEMENT OF ANGLE =one third of the angle
180-x=x/3
3(180-x)=x.
540-3x=x
-3x-x=-540
-4x=-540
x=135degree
and its supplement=180-135=45degree
Anonymous:
thanks
Answered by
34
Let one angle be x degrees. Then its supplementary angle will be 180 - x degrees.
That means the two angles will be x and 180 - x.
Given that the supplementary of an angle is 1/3rd of it.
Hence the linear equation for the given statement is,
x = 1/3 * (180 - x)
3x = 180 - x
4x = 180
x = 45.
Hence the required angles are x = 45 degrees and 180 - 45 = 135 degrees.
Hope this helps!
That means the two angles will be x and 180 - x.
Given that the supplementary of an angle is 1/3rd of it.
Hence the linear equation for the given statement is,
x = 1/3 * (180 - x)
3x = 180 - x
4x = 180
x = 45.
Hence the required angles are x = 45 degrees and 180 - 45 = 135 degrees.
Hope this helps!
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