the supplement of an angle is three times the complement of the angle.find the angel
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Answered by
1
Hello dear your answer...
Let the angle be X.
according to the given question,
=>(180-X)=3(90-X).
=>180-X=270-180
=>-X+3X=270-180
=>2X=90
X comes in left side and 2goes down
=>X=90/2
=>X=45.
Their for X is 45....
Let the angle be X.
according to the given question,
=>(180-X)=3(90-X).
=>180-X=270-180
=>-X+3X=270-180
=>2X=90
X comes in left side and 2goes down
=>X=90/2
=>X=45.
Their for X is 45....
Answered by
1
Let the angle to be solved be x
Let the supplement/compliment by y
x+y=90 Complimentary angles add up to 90 degrees.
x+3y=180 Supplementary angles add up to 180 degrees, the other angle is thrice the other compliment.
Evaluating this as a system:
x+y=90 Isolate x:
x=90−y Input into the other equation:
(90−y)+3y=180 Combine like terms, isolate y and its coefficients:
2y=90 Isolate y
y=45 Input into the first equation:
x+45=90 Isolate x:
x=45degrees
Let the supplement/compliment by y
x+y=90 Complimentary angles add up to 90 degrees.
x+3y=180 Supplementary angles add up to 180 degrees, the other angle is thrice the other compliment.
Evaluating this as a system:
x+y=90 Isolate x:
x=90−y Input into the other equation:
(90−y)+3y=180 Combine like terms, isolate y and its coefficients:
2y=90 Isolate y
y=45 Input into the first equation:
x+45=90 Isolate x:
x=45degrees
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