The supplementary angle of an angle is three times of its complementary angle then the angle is
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Let the required angle be x
∴Supplement of x=(180°-x)
Complement of x=(90°-x)
∴3*Complement of x=3(90°-x)
According to question;
Supplement of x=3*Complement of x
∴(180°-x)=3(90°-x)
180°-x=270°-3x
-x+3x=270°-180°
2x=90°
x=45°
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