Question

The surd obtained after rationalizing the
numerator of 4-√25-a/a-9
is equal to​

Answer 1

Step-by-step explanation:

Given,

$\frac{4 - \sqrt{25 - a} }{a - 9} \times \frac{4 + \sqrt{25 - a} }{4 + \sqrt{25 - a} }$

$\frac{ {4 }^{2 } - ( \sqrt{25 - a) {}^{2} } }{(a - 9 ) \times (4 + \sqrt{25 - a)} }$

$\frac{(a - 9)}{(a - 9) \times (4 + \sqrt{25 - a)} }$

$= \frac{1}{4 + \sqrt{25 - a} }$

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