Question

The surface area of a box cuboid in shape whose length breadth and height are 16cm ,8cm and 6 respectively is?​

Answer 1

Given :-

• Length of the Box = 16cm
• Breadth of the Box = 8cm
• Height of the Box = 6cm

To Find :-

• Surface Area of the Box

Solution :-

⟹ Surface Area of Box =2(lb+bh+ hl)

⟹ Surface Area = 2(16×8+8×6+6×16)

⟹ Surface Area = 2( 128 + 48 + 96 )

⟹ Surface Area = 2( 128 + 144)

⟹ Surface Area = 2 × 272

⟹ Surface Area of Box = 544cm²

Thus, Surface Area of Box = 544cm²

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★ Additional Info :

• T.S.A of cylinder = 2πrh + 2πr²
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Surface area of sphere = 4πr²
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

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Answer 2

Answer:

Solution :-

⟹ Surface Area of Box =2(lb+bh+ hl)

⟹ Surface Area = 2(16×8+8×6+6×16)

⟹ Surface Area = 2( 128 + 48 + 96 )

⟹ Surface Area = 2( 128 + 144)

⟹ Surface Area = 2 × 272

⟹ Surface Area of Box = 544cm²

Thus, Surface Area of Box = 544cm²

________________

★ Additional Info :

T.S.A of cylinder = 2πrh + 2πr²

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Surface area of sphere = 4πr²

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²

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