Question

the surface area of a closed box is 846 cm ² . if the ratio of its length, breadth and height is 5:4:3 ,then find the length breadth and height of the box​

Answer 1

Answer:

Let l=5x, b=4x, h=3x

∴ TSA of cuboid =846 cm2

⇒2(lb+bh+hl)=846⇒2(20x2+12x2+15x2)=846

⇒47x2=423⇒x2=9⇒x=3

∴ l=15,b=12,h=9

Volume of cuboid  =lbh=15×12×19=1620cm3