the surface area of a cube odd is 4150 CM square if its length and breadth and 35cm and 45cm respectively find its height
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Let h be the height of cuboid.
Length of cuboid (l)=35cm
Breadth of cuboid (b)=25cm
Surface area of cuboid =4150cm
2
We know that,
Surface area of cuboid =2(lb+bh+hl)
Therefore,
2(lb+bh+hl)=4150
⇒35×25+25h+35h=
2
4150
⇒60h=2075−875
⇒h=
60
1200
=2cm
Hence, the height of the cuboid is 2 cm.
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