The surface area of
a cuboid is 112 cm,
its length is twice its
breadth
height is
breadth
If it is
melted to form 2
identical cubes
without any wastage,
what is the volume
(in cm) of each
cube?
Answers
Answer:
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- First Let's Find Surface Area of Cuboid
Surface Area of Cuboid = 2 (lb + bh + lh)
⇒ Surface Area of Cuboid = 2 [(l × b) + (b × h) + (l × h)]
⇒ Surface Area of Cuboid = 2 [(2b × b) + (b × 1/2 b) + (2b × 1/2 b)]
⇒ Surface Area of Cuboid = 2 [(2b²) + (b²/2) + (2b²/2)]
⇒ Surface Area of Cuboid = 2 [2b² + (b²/2) + b²]
⇒ Surface Area of Cuboid = 2 [3b² + (b²/2)]
⇒ Surface Area of Cuboid = 6b² + b²
⇒ Surface Area of Cuboid = 7b² cm²
Substituting the value of Surface Area of Cuboid
⇒ 112 cm² = 7b² cm²
⇒ 112 = 7b²
⇒ 112/7 = b²
⇒ 16 = b²
⇒ √16 = √b²
⇒ 4 = b
⇒ b = 4
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Volume of 2 Cubes = Length × Breadth × Height
⇒ Volume of 2 Cubes = 2b × b × 1/2 b
⇒ Volume of 2 Cubes = 2b² × 1/2 b
⇒ Volume of 2 Cubes = b² × 1b
⇒ Volume of 2 Cubes = b³
Substitute the Value of b
⇒ Volume of 2 Cubes = 4³
⇒ Volume of 2 Cubes = 64 cm³
⇒ Volume of Cube = 64 cm³/2
⇒ Volume of Cube = 32 cm³