Question

The surface area of a cuboid is 4212 meter square if its dimensions are in ratio 4:3:2. Find the volume

Answer 1

Answer:

l=4×9=36

w=3×9=27

h=2×9=18

Step-by-step explanation:

let one angle be 'x' then l=4x,w=3x,h=2x.

as the formulae isSA=2lw+2lh+2hw, to find the surface area.

Then 2(4x)(3x)+2(4x)(2x)+2(2x)(3x)=4212

=2(12x+8x+6x)=4212

2(26x)=4212

52x=4212

x=81sqm

x=9m

there fore

l=36

w=27

h=18

Answer 2

Answer:

Let length(l) be 4a m, breadth(b) be 3a m and height(h) be 2a m

surface area of cuboid=4212 m sq.

surface area of cuboid= 2 (lb+bh+hl)

2 (4a×3a + 3a×2a + 2a×4a)=4212 m sq.

2 (12a sq.+6a sq.+8a sq.)=4212 m sq.

2× 26a sq.= 4212 m sq.

52 a sq. = 4212 m sq.

a sq.=4212/52

a sq.=81

a=9 m

l= 4a

=4×9=36m

b=3a

=3×9=27m

h=2a

=2×9=18m

Volume of cuboid=lbh

=36×27×18 cubic m

=17,496 cubic m