the surface area of a cuboid is 4212m^2.If its dimension are in the ratio 4:3:2, find the volume of the cuboid.
Answers
Answered by
1
let the dimensions be 4x,3x,2x
volume of cuboid- length× breadth× height
surface area of cuboid= 2(lb+lh+bh)
4212m²= 2(4x×3x+ 4x×2x+ 3x×2x)
4212= 2(12x²+ 8x²+ 6x²)
4212= 24x²+16x²+12x²
4212= 52x²
4212/52=x²
81=x²
9m=x
therefore the value of x is 234
4x= 9×4=36
3×= 9×3=27
2x=9×2=18
volume of cuboid= length×breadth×height
36×27×18
17496
therefore the volume of cuboid
is 17496m³
Similar questions