Question

The surface area of a cuboidal hall with dimensions 20 m x 10 m x 5m.
​

Answer 1

Answer:

Surface Area=2lw+2lh+2hw,

where, l=length, w=width and h= height.

2(20)(10)+2(10)(5)+2(5)(20)

2(200)+2(50)+2(100)

400+100+200

700 m^2

This is your answer.

Hope this helps you!

Step-by-step explanation:

Answer 2

$\huge\bold{\mathtt{Question⇒}}$

The surface area of a cuboidal hall with dimensions 20 m × 10 m × 5 m.

$\huge\bold{\mathtt{Given⇒}}$

Dimensions = 20 m × 10 m × 5 m

$\huge\bold{\mathtt{To\:find⇒}}$

The surface area.

$\huge\bold{\mathtt{Solution⇒}}$

We know that:

For a cuboid,

$\boxed{\mathtt{Surface\:Area=2(lb+bh+lh)\:unit²}}$

Where,

• l = Length

• b = Breadth

• h = Height

Here,

• l = 20 m

• b = 10 m

• h = 5 m

So, surface area

= 2(lb+bh+lh) unit²

Putting the values of l, b and h.

= 2[(20×10) + (10×5) + (20×5)] m²

= 2(200 + 50 + 100) m²

= (2×350) m²

= 700 m²

$\huge\bold{\mathtt{Hence⇒}}$

Surface area = 700 m²

$\huge\bold{\mathtt{Therefore⇒}}$

The surface area of the cuboidal hall is 700 m².

$\huge\bold{\mathtt{Done}}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

$\large\bold{\mathtt{Have\:a\:nice\:day.}}$