Math, asked by kartiksood744, 4 days ago

The surface area of a hemispherical bowl of radius 3.5cm is (in m)​

Answers

Answered by bonditanath2016
0

Answer:

0.0115395m^2

Step-by-step explanation:

Here, radius of the hemisphere,r =3.5cm

therefore, total surface area of the hemispherical bowl=3πr^2

=3*3.14*(3.5)^2

=9.42*12.25

=115.395cm^2

total surface area in metre=115.395/10000

=0.0115395m^2

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