The surface area of a hemispherical bowl of radius 3.5cm is (in m)
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Answer:
0.0115395m^2
Step-by-step explanation:
Here, radius of the hemisphere,r =3.5cm
therefore, total surface area of the hemispherical bowl=3πr^2
=3*3.14*(3.5)^2
=9.42*12.25
=115.395cm^2
total surface area in metre=115.395/10000
=0.0115395m^2
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