Question

The surface area of a right square pyramid is given by A=b2+2bh where b is the length of a side of the base and h is the slant height.solve the formula for h if b=3

Answer 1

Question :- The surface area of a right square pyramid is given by A=b²+2bh where b is the length of a side of the base and h is the slant height.solve the formula for h if b=3 ?

Solution :-

Given that,

→ surface area of a right square pyramid is A = b² + 2bh .

Now, we have given that, the length of a side of base is 3.

we have to find slant height .

So,

→ A = b² + 2bh

→ (A - b²) = 2bh

Dividing both sides by 2b , we get,

→ (A - b²)/2b = h

Putting value of b = 3 now, we get,

→ h = (A - 3²) / 2 * 3

→ h = (A - 9)/6

→ h = {(A/6) - (3/2)}. (Ans.)

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