the surface area of a solid metallic sphere is 616 cm2..it is melted and recast into a cone of height 28 cm.find the diameter of the base of the cone so formed..use pie=22/7
Answers
Answered by
208
Solution:-
Surface area of the sphere = 4πr²
616 = 4*22/7*r²
r² = (616*7)/88
r² = 4312/88
r² = 49
r = 7 cm
Radius of the sphere is 7 cm
As sphere is melted and recast into a cone then,
Volume of the sphere = Volume of the cone
4/3πr³ = 1/3πr²h
4/3*22/7*7*7 = 1/3*22/7*r²*28
4/3*7*7*7 = 1/3*r²*28
r² = 49
r = 7 cm
So, radius of the cone is 7 cm and diameter = 7*2 = 14 cm
Answer.
Surface area of the sphere = 4πr²
616 = 4*22/7*r²
r² = (616*7)/88
r² = 4312/88
r² = 49
r = 7 cm
Radius of the sphere is 7 cm
As sphere is melted and recast into a cone then,
Volume of the sphere = Volume of the cone
4/3πr³ = 1/3πr²h
4/3*22/7*7*7 = 1/3*22/7*r²*28
4/3*7*7*7 = 1/3*r²*28
r² = 49
r = 7 cm
So, radius of the cone is 7 cm and diameter = 7*2 = 14 cm
Answer.
Answered by
42
Please have a look at the attached file.
Attachments:
Similar questions