The surface area of a solid metallic sphere is 616 cm². It is melted and recast into smaller
spheres of diameter 3.5 cm. How many such spheres can be obtained?
Answers
Answer:
4πr² = 616 cm²
πr² = 616/4 = 154
r² = 1078/22 = 49
r = √49 = 7cm
V = 4/3 πr³
V = 4/3 × 22/7 × 7 × 7 × 7
V = 4/3 × 154 × 7
V = 4/3 × 1078
V = 4 × 359.3
V = 1436.76 cm³
Small spheres :
v = 4/3 × 22/7 × 3.5/2 × 3.5/2 × 3.5/2
v = 4/3 × 22 × 0.5/2 × 12.25/4
v = 4/3 × 11 × 0.5 × 12.25/4
v = 269.5/12
v = 22.45 cm³
No. of spheres can be made = V / v
=> 1436.76 / 22.45
=> approx. 63.9 or 64 spheres
Given:
The surface area of a solid metallic sphere is 616cm². It is melted and recast into smaller spheres of diameter 3.5cm.
To find:
The spheres are can be obtained.
Explanation:
We have,
The surface area of a solid sphere= 616cm²
We know that formula of the surface area of sphere: 4πr² [sq.units]
→ 4× ×r² = 616cm²
→ 88/7 × r² = 616
→ r² =
→ r² =
→ r² = (7× 7)cm
→ r² = 49cm
→ r= √49cm
→ r= 7cm.
Therefore,
We know that volume of the sphere:
Volume of the big sphere=
Volume of the big sphere=
Volume of the big sphere=
Volume of the big sphere=
Volume of the big sphere= 1437.33cm³
&
Volume of the small sphere:
We have,
- Diameter of small sphere,d= 3.5cm
- Radius of small sphere,r= 3.5/2cm
→
→
→
→
→ 22.45cm³.
- ∴ The number of smaller sphere:
⇒
⇒
⇒ 64.02 spheres
Thus,
The sphere can be obtained is 64 spheres . [approximately]