the surface area of a solid metallic sphere is 616 cmsq . it is melted and recast into a cone of height 28 cm. find the diameter of the base of the cone so formed .
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Volume of sphere = volume of cone
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Answer:-
Given:-
The height of the cone = 28 cm
Surface area of the solid metallic sphere = 616 cm3
Surface area of the sphere = 4πr²
So, 4πr² = 616
r2 = 49
r = 7
Radius of the solid metallic sphere = 7 cm
Let’s assume r to be the radius of the cone
Using formula:-
Volume of the cone = 1/3 πr²h
= 1/3 πr² (28) → (i)
Volume of the sphere = 4/3 πr³
= 4/3 π7³ → (ii)
On equating equations (i) and (ii), we have
1/3 πr2 (28) = 4/3 π7³
Eliminating the common terms, we get
r² (28) = 4 x 7³
r2 = 49
r = 7
So, diameter of the cone = 7 x 2 = 14 cm
Therefore, the diameter of the base of the cone is 14 cm
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