The surface area of a solid metallic sphere is 616cm2. It is melted and recast into a cone of height 28cm. Find the diameter of the base of the cone so formed.
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Hey.
Here is the answer.
As surface area of sphere = 4πr^2=616 cm^2
so, r^2 = 616/4π
so, r = 49.02 cm
So, volume of sphere = 4/3 π r^3
= 4/3 π (49.02)^3
= 493402.28 cm^3
= volume of the cone casted
= 1/3 π R^2 h
= 1/3 π R^2 ×28
So, 493402.28 = 1/3 π R^2 ×28
or, R^2 = 493402.28×3 /28π
or, R = 129.72 cm
So, required radius is 129.72 cm.
Thanks.
Here is the answer.
As surface area of sphere = 4πr^2=616 cm^2
so, r^2 = 616/4π
so, r = 49.02 cm
So, volume of sphere = 4/3 π r^3
= 4/3 π (49.02)^3
= 493402.28 cm^3
= volume of the cone casted
= 1/3 π R^2 h
= 1/3 π R^2 ×28
So, 493402.28 = 1/3 π R^2 ×28
or, R^2 = 493402.28×3 /28π
or, R = 129.72 cm
So, required radius is 129.72 cm.
Thanks.
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