Question

the surface area of a sphere is 5544cm² , find its please its urgent please fast 1 st correct i will mark brainliest give thanks to both and rate wrong answers will be reported

Answer 1

r2 =5544

r2 = 441

r = 21cm

Now

Volume = 4/3πr3

= 4/3 × 22/7 ×21×21×21

= 38808cm3

OR

Surface area of a sphere = 5544cm^2

4pie r^2 = 5544

r^2 = 441cm

r = 21cm.

Now,

Volume of a sphere = 4/3 pie r^3..

= 4/3 × 22/7 × 21 ×21 ×21

= 38808 cm^3

Answer 2

$\displaystyle\huge\red{\underline{\underline{Solution}}}$

A sphere is defined as the set of points that are exactly some given distance from some specified centre point.

PROPERTIES

1. General equation of a sphere with centre at origin & radius r unit is given by

${x}^{2} + {y}^{2} + {z}^{2} = {r}^{2}$

2. The surface area of a sphere of radius r unit is

$= 4\pi {r}^{2} \: \: sq \: uit$

3. Volume of a sphere of radius r unit is

$= \frac{4}{3} \pi {r}^{3} \: \:$

CALCULATION

Let radius of the sphere = r cm

So The surface area of the sphere

$= 4\pi {r}^{2} \: \: sq \: uit$

Therefore

$4\pi {r}^{2} \: = 5544$

$\implies \: 4 \times \frac{22}{7} \times {r}^{2} = 5544$

$\implies \: {r}^{2} \: = 5544 \times \frac{7}{22} \times \frac{1}{4}$

$\implies \: {r}^{2} \: = 441$

$\therefore \: r \: = 21$

Hence the required radius = 21 cm

Also Volume of a sphere

$= \frac{4}{3} \times \pi \times {21}^{3} \: \: \: {cm}^{3}$

$= 38808 \: \: {cm}^{3}$