The surface area of cuboid is 758 CM^2 .its length and breadth are 14 cm and 11cm respectively. find its height
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Surface Area of cuboid =2(lb+bh+hl)
Surface Area of cuboid = 758 sq. cm ( given )
length = 14 cm
breadth = 11 cm
height = ? cm
ATQ
2(lb+bh+hl) = 758
lb + bh + hl = 758/2
lb + bh + hl = 379
14 x 11 + 11h + 14 h = 379
154 + 25h = 379
25 h = 379 - 154
25h = 225
h = 225/25
h = 45/5
h = 9 cms.
hope this helps you out!
Surface Area of cuboid = 758 sq. cm ( given )
length = 14 cm
breadth = 11 cm
height = ? cm
ATQ
2(lb+bh+hl) = 758
lb + bh + hl = 758/2
lb + bh + hl = 379
14 x 11 + 11h + 14 h = 379
154 + 25h = 379
25 h = 379 - 154
25h = 225
h = 225/25
h = 45/5
h = 9 cms.
hope this helps you out!
Anonymous:
6brain9 thanks a lot
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4
Here is your answer.Height=9 cm.
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