the surface area of cuboid is 758 cm square. its length and breadth are 14 cm and 11 cm respectively. find its height.
Answers
Answered by
221
Surface Area of cuboid =2(lb+bh+hl)
Surface Area of cuboid = 758 sq. cm ( given )
length = 14 cm
breadth = 11 cm
height = ? cm
ATQ
2(lb+bh+hl) = 758
lb + bh + hl = 758/2
lb + bh + hl = 379
14 x 11 + 11h + 14 h = 379
154 + 25h = 379
25 h = 379 - 154
25h = 225
h = 225/25
h = 45/5
h = 9 cms.
Surface Area of cuboid = 758 sq. cm ( given )
length = 14 cm
breadth = 11 cm
height = ? cm
ATQ
2(lb+bh+hl) = 758
lb + bh + hl = 758/2
lb + bh + hl = 379
14 x 11 + 11h + 14 h = 379
154 + 25h = 379
25 h = 379 - 154
25h = 225
h = 225/25
h = 45/5
h = 9 cms.
Shayaan240283:
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Answered by
49
surface area of cuboid = 758
surface area of cuboid = 2 ( lh + bh + lb )
l = 14, b = 11
h =?
2 ( 14×h+11×h + 11 × 14)=758
2 ( 11 h+14h+154)=758
25h+154=758/2
25h=379-154
h=225/25
h=9 cm
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