Question

the surface area of solid cylinder of radius 2.0 cm and height 10.0cm is equal to __(mm)²​

Answer 1

Step-by-step explanation:

$= > 2\pi \: rh + 2\pi \: {r}^{2} = 2\pi \: 20 + 2\pi \: 4 \\ = > 2\pi \: 2(10 + 2) \\ = > 4\pi(12) \\ = > 48\pi \: {cm}^{2} \\ = > 4800\pi \: {mm}^{2}$

Answer 2

Step-by-step explanation:

${\small{\sf{r = 2 \ cm}}}$

${\small{\sf{h=10 \ cm}}}$

We know that ,

${\small{\sf{T.S.A_{(cylinder)} = 2 \pi r(r+h)}}}$

${\twoheadrightarrow{\small{\sf{T.S.A_{(cylinder)} = 2 × \dfrac{22}{7} × 2 \ cm \ (2cm + 10cm)}}}}$

${\twoheadrightarrow{\small{\sf{T.S.A_{(cylinder)}=\dfrac{88}{7}cm × 12cm}}}}$

${\twoheadrightarrow{\small{\sf{T.S.A_{(cylinder)} = \dfrac{1056}{7}cm^{2} }}}}$

${\twoheadrightarrow{\small{\sf{T.S.A_{(cylinder)} = 150.85714286cm^2 \approx 150.8572 cm^2}}}}$

${\leadsto{\small{\sf{ \red{T.S.A_{(cylinder)} \ in \ mm^2 = (150.8572×100)mm^2 = 15085.72mm^2}}}}}$