The surface area of the endd of a brick is 50cm sq.The surface area of the base of another brick is 200 cm sq Each brick weigh 50 N . What pressure each of the brick exerts on the ground
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Pressure = Force/Area
Base of the end of the brick 1 = 50 cm²
Base of the end of the brick 2 = 200 cm²
Weight of both the breaks = 50 N
[1 m² = 10000 cm²]
1:-
P = F/A ⟹ P = (50 kg m/s²)/(50 cm²)
⟹ P = (50 kg m/s²)/(50 ÷ 10000 m²)
⟹ P = 10000 N/m² = 10000 Pa
2:-
P = F/A ⟹ P = (50 kg m/s²)/(200 cm²)
⟹ P = (50 kg m/s²)/(200 ÷ 10000 m²)
⟹ P = 2500 N/m² = 2500 Pa
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