Physics, asked by JSAKETH2005, 7 months ago

The surface charge density of a sphere of radius r, is σ. It is placed at a point A. The electric field intensity at B due to this sphere is E. Another charge sphere of radius 2r is placed at B. If the intensity at the centre of A and B is E/2, then the surface charge density of B is ?

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Answered by sohamkdeb
0

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Hey here is your answer

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Answered by arunajyothisakilam
4

the answer is 7sigma/32

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