The surface charge density of a thick metal plate is sigma the electric field near the surface is
Answers
Answered by
0
Answer:
Explanation:
According to gauss theorem
E= q/ε
Here q is the charge of the conductor
now, σ=q/ds
q=σds
Hence, E.dscosθ = σds/ε
As the unit vector is normal to to the surface in the upward direction. Hence the angle between the electric field and area vector is 0
E.ds = σds/ε
E=σ/ε
Similar questions