Physics, asked by neelikeerthi9746, 1 year ago

The surface energy of a liquid drop of radius r is proportional to(a) r³(b) r²(c) r(d) 1/r

Answers

Answered by mandeepkaur0
0

option b is right

r^2

since, we know that surface energy = surface tension * area

so,

area =4*pi*r^2

now,

surface energy is proportional to 4 pi *r^2

hence,

r^2 is the right answer

plzzz mark my answer as a BRAINLIEST my friend

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