Question

The surface of a glass plate (index of refraction n3 = 1.50) is coated with a transparent thin film (index of refraction n2 = 1.25).

Answer 1

Answer:

Explanation:

Surface of glass plate is then with respect to coated thin film(according to question)

i.e.2 n 3 Where,n is the refractive index of 3 with respect to 2

i.e. n3/n2

i.e.1.50/1.25

i.e.1.2

Answer 2

Answer:

(a) c = f λ … 3x108 = f (6x10– 7) … f = 5x1014Hz.

(b) n1 λ1 = n2 λ2 … (1) (6x10– 7) = (1.25) = 4.8x10– 7 m = 480 nm

(c) The light is heading out to dynamically increasingly thick materials, so experiences ½ λ stage shifts at the two limits S1 and S2 basically counterbalancing this stage move (from flips). To get least force (damaging), the absolute stage move from going in the film ought to be ½ λfilm so the film thickness ought to ¼ λfilm = ¼ 480 nm = 120 nm

(d) Based on a similar examination above. To get most extreme force (useful) the absolute stage move from going in the film ought to be 1 λfilm, so the film thickness ought to be ½ λfilm = ½ 480 nm = 240 nm