Physics, asked by akhil57541, 7 months ago

The surface of a liquid is just able to support the weight of a six-legged insect. The leg ends can be assumed to be spheres each of radius 3.2 × 10−5 m and the weight of the insect is distributed equally over the six legs. The coefficient of surface tension in this case is 0.1 N/m and the angle of the footfall with respect to the vertical is θ = π/3 radians (see figure). The mass of the insect is close to (A) 5×10−5 kg (B) 5×10−6 kg (C) 1×10−6 kg (D) 1×10−7

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Answered by Anonymous
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