Question

The surface of the water in a well is at −25 feet with respect to the ground.

If a pump pumps out water such that the water level reduces by 2 feet every 15 minutes, what will be the water level of the well, with respect to the ground, after 2 hours?

The initial water level of the well with respect to the ground = _______
feet

The change in the water level during pumping of 2 hours = ______
feet

The water level of the well after 2 hours of pumping = ______
feet

Answer 1

GiVEN

• Level of well is -25 feet w.r.t Ground
• Pump pumps out 2 feet of water level per 15 min

SOLUTiON

USiNG UNiTARY METHOD

• Water level reduces 2 feet per 15 min
• Water level reduces 8 feet per 1 hr
• Water level reduces 16 feet per 2 hr

AÑSWER

• The initial water level of the well with respect to the ground = -25 feet
• The change in the water level during pumping of 2 hours = 16 feet
• The water level of the well after 2 hours of pumping = -9 feet

Answer 2

Answer;

Given : the surface of the water in a well is at minus 25 feet with respect to the ground.

if a pumpkin out water does the water level reduces to feet every 15 minutes.

After 2 hours the water level of the well with respect to the ground will be 16 feet .

[ by using unitary method]

now

the initial water level of the well with respect to the ground = -25 feet

the change in water level during pumping of 2 hours = 16 feet.

the water level of the well after 2 hours of pumping= 9 feet

hope it helps you ☺️