Question

the surface tension of a soap solution is 0.03N/m .find the work done in blowing a soap bubble having 10cm radius​

Answer 1

Answer:

The work done in blowing a soap bubble of 10 cm radius is given surface tension of soap bubble

The work done is blowing a soap bubble of 10 cm radius is (surface tension of soap solution is 0.03 N/m.

Answer 2

Answer:

$W= 75.42\times 10^{-4}J$

Explanation:

Given,

Tension(T) = 0.03N/m

Radius of the soap bubble(r) = 10cm

$=10^{-1}m$

To Find :-

Work done(W)

Formula Required :-

Work Done = 2 × Area of soap bubble × Tension

W = 2 × 4πr^2 × T

Solution :-

$W=2\times 4\times \dfrac{22}{7}\times (10^{-1})^2\times 0.03$

$=8\times \dfrac{22}{7}\times 10^{-2}\times 0.03$

$=\dfrac{8\times 22\times 10^{-2}\times 0.03}{7}$

$=\dfrac{176\times 10^{-2}\times 3\times 10^{-2}}{7}$

$=\dfrac{528\times 10^{-4}}{7}$

$= 75.42\times 10^{-4}J$

$W= 75.42\times 10^{-4}J$

Know More :-

$W=\dfrac{F.S}{t}$

W = mgh