The surface tension of water is 72dynecm-1.find its surface energy
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area is missing ..
surface energy = surface tension × area
surface energy = surface tension × area
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Surface Tension = 72 dyne / cm = 72 * 10^-5 N /10^-2 m = 0.072 N/m
= 0.072 N/m * 1 m /1m = 0.072 N-m/m^2 = 0.072 J/m^2
so surface energy = 0.072 Joules per m^2 area.
= 0.072 N/m * 1 m /1m = 0.072 N-m/m^2 = 0.072 J/m^2
so surface energy = 0.072 Joules per m^2 area.
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