Physics, asked by nikhileshkumar0986, 9 months ago

The surfaces between the wall, 2m' block and surfaces between the two blocks are rough The system is in equilibrium,
then choose the correct options. (F is horizontal)
Rough
Rough
F
2m
m
Smooth​

Answers

Answered by Anonymous
0

Answer:

For 10kg block, f is frictional force

f

1max

1

μ

2

1

(10g)=0.1(10×10)=10N

i) if F=2N then acting friction

f

1

=F=2N

(A) is correct.

for 5 kg block;

f

2max

=μ(10+5)g=0.3×15×10=45N

ii) if F=30N then;

F−F

1max

=10a

10a=30−10=20

a=2m/s

2

(B) is correct.

iii) if μ

1

changed to 0.5;

then f

1max

1

(10g)=0.5×10×10=50N

In the case acting friction will be F

2max

Since,

F

1max

=F

2max

Block 10kg and 5kg both move together then F

min

to begin is

F

min

−F

max

=0

F

min

=F

2max

=45N

(c) is correct.

iv) if μ=0.1 , then f

max

=10N and,

f

2max

=45N

f

2max

>f

1max

always for any any value of N. Hence, 5kg block never move on the ground.

So, option (A), (B), (C), and (D) are correct.

solution

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