Question

The symmetric difference to A and B is not equal to

Answer 1

A. $\quad(A-B) \cap(B-A)$

В. $\quad(A-B) \cup(B-A)$

C. $\quad(A \cup B)-(A \cap B)$

D. $\quad\{(A \cup B)-A\} \cup\{(A \cup B)-B\}$

The symmetric difference to A and B is not equal to a. $\quad(A-B) \cap(B-A)$ .

Step-by-step explanation:

The symmetric difference to A and B is given by

$A \Delta B &=(A-B) \cup(B-A)$

$&=(A \cup B)-(A \cap B)$

$&=(A \cup B)-A) \cup((A \cup B)-B)(\text { distribution Law})$

So the symmetric difference to A and B is not equal to $\quad(A-B) \cap(B-A)$

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