The synthesis of 3-octyne is achieved by adding a
bromoalkane into a mixture of sodium amide and an alkyne.
The bromoalkane and alkyne respectively are
(a) BrCH₂CH₂CH₂CH₂CH₃ and CH₃CH₂C ≡ CH
(b) BrCH₂CH₂CH₃ and CH₃CH₂CH₂C ≡ CH
(c) BrCH₂CH₂CH₂CH₂CH₃ and CH₃C ≡ CH
(d) BrCH₂CH₂CH₂CH₃ and CH₃CH₂C ≡ CH
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BrCH₂CH₂CH₂CH₃ and CH₃CH₂C ≡ CH are the 2 compounds.
Explanation:
- The 1st reactant is an alkyne.
- The reagent is sodium amide.
- In presence of sodium amide, alkyne reacts with the sodium amide.
- The acidic hydrogen of alkyne gets replaced by sodium forming sodium alkyne and ammonia gas.
- The sodium salt of alkyne then reacts with the alkyl bromide forming the longer chain of alkyne and the sodium bromide.
- So the alkyne is formed.
For more information about sodium and alkyne reaction,
https://brainly.in/question/5303561
Which of the following reaction doesn’t support the acidic nature of alkyne?
(a) Reaction with HBr
(b) Reaction with Grignard reagent
(c) Reaction with ammoniacal Silver salt
(d) Reaction with metallic sodium
https://brainly.in/question/13260044
Reaction of alkyne with sodium and liquid ammonia - Brainly.in
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