The system given by equation y(t-2a)-3y(t-a)+2y(t)=x(t-a) is?
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Given, y(t-2a)-3y(t-a)+2y(t)=x(t-a), then
Taking Laplace transform, e-2as Y(s)-3e-as Y(s)+2Y(s)=e-as X(s),
Hence, H(s)=e−as/(1−e−as)(2−e−as)
To find the stability, we should have, ∫∞−∞H(s)ds>0
Hence, ∫∞−∞e−as/(1−e−as)(2−e−as)ds
Let, e−as=z
=>−ae−as ds=dz
It is stable.
The system given by equation y(t-2a)-3y(t-a)+2y(t)=x(t-a) is stable.
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