The system has a no solution
2x+y=5
4x + 2y = 10
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2×1+3=5
4×2+2×1=10
Hope it helps you!!!..
Answered by
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The given system of equations is: 2x + y- 5 = 0 4x + 2y –10 =0
The above equations are of the form
a1 x + b1 y − c1 = 0 a2 x + b2 y − c2 = 0
Here,
a1 = 2, b1 = 1, c1 = −5 a2 = 4, b2 = 2, c2 = −10
So according to the question,
we get
a1/a2 = 2/4 = 1/2
b1b2 = 1/2
and, c1/c2= −5/−10− = 1/2
⇒ a1a2= b1b2= c1c2
Hence, we can conclude that the given system of equation has infinity many solutions.
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