the system of equation 2 X + 3 y - 7 = 0 and 6 X + 5 y - 11 = 0 has solution
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2x+3y-7=0
6x+5y-11=0
we will take the 7th and the 11th term to other side
2x+3y=7.......1
6x+5y=11......2
while taking the number to your right hand side the signs will change -7 will become 7 and -11 will become 11
2x+3y=7......3
6x+5y=11.......4
multiplying the 3rd term by 5
multiplying the 4th term by 3
10x+15y=35....5
18x+15y=33.....6
- - -.......by subtracting ( signs will change)
15y will get cancelled because of - and + signs
=-8x=2
x=-8 upon 2
x=-4
substituting the value x=-4 in equation no 1
2x+3y=7.....(1)
2(-4) +3y = 7
-8+3y =7
3y =7+8....(- sign will become + )
3y=15
y=15 upon 3
y= 5
Answer
x=-4 and y=5
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