Question

The system of equation 4x -y-4 =0 and 4x+y-12=0 has

Answer 1

Answer:

4x-y-4=0

4x+y-12=0

4x-y=4......eq1

4x+y=12....eq2

______

8x=16

x=16/8

x=2...... eq 3rd

now put eq 3 in eq1

4x-y=4

4(2)-y=4

8-y=4

-y=4-8

-y=-4

y=4

Answer 2

Answer:

4x-y-4=0 .............eq 1

4x+y-12=0............eq 2

Add:- 4x-y=4

+4x+y=12

= 8x=16

x= 16/8=2

x=2

Put x=2 in eq 1

4x-y=4

= 4(2)-y=4

8-y= 4

-y= -4

y= 4

Step-by-step explanation:

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