Question

The system of equations 3x+2y=1 and x+2y-3=0 has *

1 point

a) y value but has no x value

b) both x and y value

c) neither x nor y value

d) x value but has no y value

​

Answer 1

b ) equations have both X and y values .

Answer 2

$Given \: system \: of \: equations:$

$3x + 2y = 1 \: --(1)$

$x + 2y = 3 \: ---(2)$

/* Subtract equation (2) from equation (1) , we get */

$2x = -2$

$\implies x = \frac{-2}{2}$

$\implies x = -1$

/* Put x = -1 in equation (2) , we get */

$-1 + 2y = 3$

$\implies 2y = 3+1$

$\implies y = \frac{4}{2}$

$\implies y = 2$

Therefore.,

$\red{ (x,y) } \green { = ( -1,2) }$

$Option \: \pink { ( b ) } \: is \: correct.$

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